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Q.

The weight of tea in 70 packets are shown in the following table , then the mean weight of packets using step deviation method is,


Question Image

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a

201.96

b

202.96

c

203.96

d

204.96 

answer is A.

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Detailed Solution

Given table is,
Question ImageWe know,
 The formula for finding mean using the step deviation method is given by X ¯ = Mean =A+ ∑ i=1 n f i u i ∑ i=1 n f i ×h  
Consider the table,
Question ImageWe substitute,
A=202.5, ∑ f i =70, ∑ f i u i =−38   and h=1  
Therefore,
  X ¯ =A+ ∑ f i u i ∑ f i ×h ⇒ X ¯ =202.5+ −38 70 ×1  
Mean  =202.5+ −38 70 ×1 ⇒Mean = (202.5×70)−38 70 ⇒Mean = 14175−38 70 ⇒Mean = 14137 70 ⇒Mean =201.96  
Therefore, the mean weight of packets found by the step deviation method is 201.96 gram.
Therefore, option 1 is correct.
 
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The weight of tea in 70 packets are shown in the following table , then the mean weight of packets using step deviation method is,