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Q.

The weight of $1 \times 10^{22}$ molecules of ${CuSO}_{4} \cdot 5 H_{2} O$ is:

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a

0.4159 g

b

41.59 g

c

415.9 g

d

4.159 g

answer is C.

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Detailed Solution

The weight of $1 \times 10^{22}$ molecules of ${CuSO}_{4} \cdot 5 H_{2} O$ is:

$\frac{10^{22}}{N_{A}} \times 249 .5$

$\frac{10^{22}}{60} \times 249 .5 = 4.159 g$ .

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