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Q.

The weight of $H_{2} C_{2} O_{4} \cdot 2 H_{2} O$ required to prepare $500 ml$ of $0.2 N$ solution is

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a

126g

b

63 g

c

6..3 g

d

12.6g

answer is D.

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Detailed Solution

1000 ml of 1 N oxalic solution= 63 g

500 ml of 0.2 N oxalic acid solution

$= \frac{63}{1000} \times 500 \times 0.2 = 6.3 g .$

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The weight of H2C2O4⋅2H2O required to prepare 500ml of 0.2N solution is