The weight percentage of nitrogen in urea (NH₂CONH₂), is

$$\begin{gathered} \mathrm{Weight}\% \mathrm{of} \mathrm{N}=\frac{\mathrm{Molecular} \mathrm{mass} \mathrm{of} \mathrm{N}\times \mathrm{Number} \mathrm{of} \mathrm{N} \mathrm{present} \mathrm{in} \mathrm{urea}}{\mathrm{Molecular} \mathrm{mass} \mathrm{of} \mathrm{urea}}\times 100 \\ \mathrm{Weight}\% \mathrm{of} \mathrm{N}=\frac{14\times 2}{60}\times 100=46.6 \end{gathered}$$