The work done by the force $\overline{\mathrm{F}}=2\overline{\mathrm{i}}-3\overline{\mathrm{j}}-2\overline{\mathrm{k}}$ in moving a particle from (3, –2, 5) to (1, –4, 3) is

$$\begin{gathered} Force = \overline{\mathrm{F}}=(2,-3,-2), Let A\left(3,-2,5\right), B\left(1,-4,3\right) \\ \therefore Displacement = \overline{\mathrm{AB}}=(-2,-2,-2) \\ \mathrm{Work} \mathrm{done} \mathrm{w} =\overline{\mathrm{F}}\cdot \overline{\mathrm{AB}}=\left(2\hat{i}-3\hat{j}-2\hat{k}\right).\left(-2\hat{i}-2\hat{j}-2\hat{k}\right)=-4+6+4=6 \end{gathered}$$