The work done in carrying a charge q once round a circle of radius ' a ' with a charge Q at its centre is

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$\frac{q Q}{4 π ε_{0} a}$

$\frac{q Q}{4 π ε_{0} a^{2}}$

$\frac{q}{4 π ε_{0} a}$

zero

answer is D.

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Detailed Solution

The electric potential at any point on circle of radius a due to charge Q at its centre is
$V = \frac{1}{4 π ε_{0}} \frac{Q}{a}$
It is an equipotential surface
Hence, work done in carrying a charge q round the circle is zero

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