The work done in dragging a stone of mass 100 kg up an inclined plane 1 m in 100 through a distance of 10 m is (take g = 9.8 $m/s^2$)

Slope of inclined plane, sin $\theta$ = $\frac{1}{100}$

Component of weight down the inclined plane

F = mg sin $\theta$ = 100$\times$9.8$\times$ $\frac{1}{100}$ = 9.8 N

s = distance moved = 10 m

W = Fs = 9.8 $\times$10 = 98 J