The work done in increasing the P.D. across the plates of a capacitor from 4V to 6V is W. The further work done in increasing the P.D. from 6V to 8V is

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$\frac{7 W}{5}$

$\frac{4 W}{3}$

$\frac{3 W}{4}$

$\frac{5 W}{7}$

answer is C.

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Detailed Solution

$\begin{aligned} W = U_{f} - U_{i} = \frac{1}{2} C (6 V)^{2} - \frac{1}{2} C (4 V)^{2} \\ W_{2} = U_{f} - U_{i}; \frac{1}{2} C (8 V)^{2} - \frac{1}{2} C (6 V)^{2} \end{aligned}$

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