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The work done in lifting $200 kg$ of water through a vertical height of $6$ metres is ____ $Joules$ . (Assume $g = 10 m / s^{2}$ ).

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Detailed Solution

The work done in lifting

200 kg

of water through a vertical height of

6

metres is

12000 Joules

.
Given data:
Mass,

m = 200 kg

Height,

h = 6 m

Acceleration due to gravity,

g = 10 m s^{- 2}

Find the work done.
Formula used:
Work done,

W = mgh

Where

m

is the mass of the object and

h

is the height of the object.
Now,

W = mgh

W = 200 \times 10 \times 6

W = 12000 J

Hence, the work done is

12000

joules.

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