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The work done in moving a body of mass 4 kg with uniform velocity of 5 $m s^{- 1}$ for 10 seconds on a surface of $μ$ = 0.4 is (take g = 9.8 $m / s^{2}$ )

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484 J

584 J

784 J

684 J

answer is B.

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Detailed Solution

Force to be applied (against friction),

F = $μ$ mg = 0.4 $\times$ 4 $\times$ 9.8 = 15.68 N

Displacement, s = vt = $5 \times 10 = 50 m / s$

Work = $F s =$ $15.68 \times 50 = 784 J$

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