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Q.

The work done in rotating a magnet of magnetic moment $2 {Am}^{2}$ in a magnetic field of $5 x 10^{- 3} T$ from the direction along the magnetic field to opposite direction to the magnetic field, is

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a

$10 J$

b

Zero

c

$2 x 10^{- 2} J$

d

$10^{- 2} J$

answer is B.

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Detailed Solution

$W = MB (1 - cosθ), where θ = 180^{o}$

$\Rightarrow W = 2 MB \Rightarrow W = 2 x 2 x 5 x 10^{- 3} = 2 x 10^{- 2} J$

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The work done in rotating a magnet of magnetic moment 2 Am2 in a magnetic field of 5 x 10-3 T from the direction along the magnetic field to opposite direction to the magnetic field, is