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Q.

The work done in the isothermal reversible expansion of argon gas at $27^{0} C$ from 4L to 16L was equal to 4200 cal. What is the amount of argon subjected to such an expansion? $(A r = 40, \ln 4 = 1.4)$ (R value in Cal)

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a

5.0g

b

20.0g

c

48.1g

d

200.0g

answer is C.

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Detailed Solution

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$W = - nRT \ln \frac{P_{1}}{P_{2}}$

$\begin{array}{l} - 4200 = \frac{- W}{40} \times 2 \times 300 \times 1 n \frac{16}{4} \\ ∴ W = 200 g \end{array}$

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