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The work done in twisting a steel wire of length 25 cm and radius 2 mm through 45° will be: $(η = 8 \times 10^{10} N / m^{2})$

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15.47 J

3.1 J

2.48 J

18.79 J

answer is A.

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Detailed Solution

$W = \frac{1}{2} C θ^{2} = \frac{{πηr}^{4} θ^{2}}{4 l} = \frac{3.14 \times 8 \times 10^{10} \times {(2 \times 10^{- 3})}^{4} \times {(π / 4)}^{2}}{4 \times 25 \times 10^{- 2}} = 2.48 J$

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