Q.

The work done on a particle of mass m by a force F=k(xi^+yj^)x2+y23 (where k being a constant), when the particle is taken from the point (a,0) to the point (0,a) along a circular path of radius a about the origin in the XY plane, is

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a

zero

b

πk2a

c

2πka

d

πka

answer is D.

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Detailed Solution

W=Fxdx+Fydy

In this case the force is radial, and the particle is moving along a circular path,  so, Fds.

W=0

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