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Q.

The work function for a metal is 4 eV.  To eject the photo electrons with zero velocity the wavelength of the incident light should be

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a

1700 A0

b

5900 A0

c

3100 A0

d

2700 A0      

answer is D.

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Detailed Solution

 

{W_o} = \frac{{hc}}{{{\lambda _o}}} = \frac{{12400eV{A^o}}}{{{\lambda _o}}}
\therefore {\lambda _o} = \frac{{12400eV{A^o}}}{{4eV}}
\therefore {\lambda _o} = 3100{A^o}\
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