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The work function for a metal is To emit a photo electron of Zero velocity from the surface of the metal ,The wave length of incident light should be

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$2700 A^{0}$

$1700 A^{0}$

$5900 A^{0}$

$3100 A^{0}$

answer is D.

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Detailed Solution

${hϑ=hϑ}_{0} + K . E (F o r z e r o v e l o c i t y K . E = 0), h ϑ = h ϑ_{0} h ϑ = 4 e v \frac{h c}{λ} = 4 e v λ = \frac{h c}{4 e v} = \frac{6 .625 \times 10^{- 34} \times 3 \times 10^{8}}{4 \times 1 .6 \times 10^{- 19}} = 3100 A^{0}$

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