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The work function for sodium surface is 2.0 eV and that for aluminum surface is 4.2 eV. The two metals are illuminated with appropriate radiations so as to cause photoemission. Then

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the threshold frequency for sodium will be less than that for aluminum

the threshold frequency of sodium will be more than that of aluminum

both sodium and aluminum will have the same threshold frequency

none of the above

answer is A.

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Detailed Solution

As work function $W = h v_{0}$ , where $v_{0}$ is the threshold frequency.
Greater the work function, greater is the threshold frequency.

Therefore, the threshold frequency of sodium will be lesser than that for aluminum.

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