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The work function of a metal is 31 eV. To eject a photoelectron of zero velocity from the surface of the metal the wavelength of incident light should be above

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400A⁰

40A⁰

200A⁰

20A⁰

answer is A.

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Detailed Solution

$λ (A^{0}) = \frac{12400 eV}{31 eV}$ = 400

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