Q.

The work function of a potassium is 2.0eV. When it is illuminated by light of wavelengths 3300 A0 photo electrons are emitted. The stopping potential of photo electrons is (in Volts)

[Plank’s constant h= 6.6×10-34ms-1Js,1Ev =1.6×10-19J, C=3×108ms-1]

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answer is 1.75.

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Detailed Solution

E=124203300eV=3.75eVϕ=2.0eVeVS=Eϕ=1.75eV

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The work function of a potassium is 2.0eV. When it is illuminated by light of wavelengths 3300 A0 photo electrons are emitted. The stopping potential of photo electrons is (in Volts)[Plank’s constant h= 6.6×10-34ms-1Js,1Ev =1.6×10-19J, C=3×108ms-1]