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Q.

The work functions of metals A and B are in the ratio 1 : 2. If light of frequenciesf and 2f  are incident on metal surfaces of A and B respectively, the ratio of the maximum kinetic energies of photo electrons emitted is (f is greater then threshold frequency of A, 2f is greater than threshold frequency of B

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a

1 : 3

b

1 : 2

c

1 : 1

d

1 : 4

answer is B.

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Detailed Solution

hv=w+kE

kE=hv−w

kE=hf−w

kE2=2hf−2w

        =2(hf−w)

kE1kE2=12

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