The work of 146 kJ is performed in order to compress one kilo mole of a gas adiabatically and in this process the temperature of the gas increases by 7°C . The gas is : $(R = 8 .3 {Jmol}^{- 1} K^{- 1})$ $Take γ = \frac{2}{f} + 1, f is degrees of freedom.$

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monoatomic

triatomic

diatomic

A mixture of monoatomic and diatomic

answer is C.

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Detailed Solution

$\begin{array}{l} W = \frac{ηR}{(γ - 1)} [T_{1} - T_{2}] \\ 146000 = \frac{1000 \times 8 .3}{(γ - 1)} [7] \\ γ - 1 = \frac{58 .1}{146} \\ γ = 1 + 0 .4 = 1 .4 \end{array}$

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