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Q.

The workdone by Carnot engine operating between temperatures $127^{o} C$ and $27^{o} C$ is 2 KJ. The amount of heat transferred to the engine by the reservoir is (in KJ)

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Detailed Solution

In a carnot engine, $\frac{W}{Q} = \frac{T_{h o t} - T_{c o l d}}{T_{n o t}}$

$Q = \frac{W \times T_{h o t}}{T_{h o t} - T_{c o l d}} = \frac{2 \times (127 + 273)}{(127 + 273) - (27 + 273)} = \frac{2 \times 400}{100} = 8 k J$

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