The working substance of a heat engine is monoatomic ideal gas. Determine the efficiency (in percentage) of heat engine; the cycle is shown in the figure

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answer is 15.

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Detailed Solution

$W = \frac{1}{2} \times 3 V_{0} \times p_{0} = \frac{9 p_{0} V_{0}}{2}$

$Q_{g i v e n} i s f r o m 1 t o 2 = \frac{1}{2} \times (p_{0} + 4 p_{0}) \times 3 V_{0} + \frac{3}{2} \times (16 p_{0} V_{0} - p_{0} V_{0})$

$= \frac{15 p_{0} V_{0}}{2} + \frac{45 p_{0} V_{0}}{2} = 30 p_{0} v_{0} η = \frac{9 p_{0} V_{0}}{30 p_{0} V_{0}} \times 100 = \frac{3}{20} \times 100 = 15$

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