The x and y coordinates of the particle at any time are x = 5t - $2t^2$ and y = 10t respectively, where x and y are in metres and t in seconds. The acceleration of the particle at t = 2 is

Displacement along x-axis,

$x=5t-2t^2$

Velocity along x-axis,

$\Rightarrow v_x=\frac{dx}{dt}=5-4t$

Acceleration along x-axis,

$\Rightarrow a_x=\frac{d{v}_x}{dt}=-4\mathrm{m}/{\mathrm{s}}^2$

Displacement along y-axis, y = 10 t

Velocity along y-axis,  $\Rightarrow v_y=\frac{dy}{dt}=10$

Acceleration along y-axis = 0,

as velocity is constant.
So, acceleration = -4 m/s² along x-axis.