Q.

The yield of alkyl bromide obtained as a result of heating the dry silver salt of carboxylic acid with bromine in CCl4 is

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a

10 > 30 > 20 bromides

b

30 > 10 > 20 bromides

c

30 > 20 > 10 bromides

d

10 > 20 > 30 bromides

answer is B.

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Detailed Solution

This is Hunsdicker reaction. In this reaction intermediate formed is alkyl free radical. Alkyl free radical and bromine free radical under goes head on collisions to form alkyl bromide with one carbon less. As branching on free radical increases head on collisions decreases between R° and Br°. With 30 free radical elimination reaction also occurs.

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