The Young’s double slit experiment is performed with blue and with green light of wavelengths 4360 A0 and 5460 A0 respectively. If x is the distance of 4th maximum from the central one, then

x b l u e x g r e e n = 5460 4360

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The Young’s double slit experiment is performed with blue and with green light of wavelengths 4360 $\overset{0}{A}$ and 5460 $\overset{0}{A}$ respectively. If x is the distance of 4th maximum from the central one, then

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$x (b l u e) = x (g r e e n)$

$x (b l u e) > x (g r e e n)$

$x (b l u e) < x (g r e e n)$

$\frac{x (b l u e)}{x (g r e e n)} = \frac{5460}{4360}$

answer is C.

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$D i s \tan c e o f n t h m a x i m a, x = n λ \frac{D}{d} ∴ x \propto λ A s λ_{b} < λ_{g} ∴ x_{b l u e} < x_{g r e e n}$

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