The Young's modulus of a rubber string 8 cm long and density 1.5 kg/m3 is 5×108 N/m2 , is suspended on the ceiling in a room. The increase in length due to its own weight will be

l=L2dg2Y=(8×10−2)2×1.5×9.82×5×108=9.6×10−11m

l=L2dg2Y=(8×10−2)2×1.5×9.82×5×108=9.6×10−11m

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The Young's modulus of a rubber string 8 cm long and density $1 .5 kg / m^{3}$ is $5 \times 10^{8} N / m^{2}$ , is suspended on the ceiling in a room. The increase in length due to its own weight will be

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$9 .6 \times 10^{- 11} m$

$9 .6 \times 10^{- 5} m$

$9 .6 \times 10^{- 3} m$

$9.6 m$

answer is B.

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$l = \frac{L^{2} dg}{2 Y} = \frac{{(8 \times 10^{- 2})}^{2} \times 1 .5 \times 9 .8}{2 \times 5 \times 10^{8}} = 9 .6 \times 10^{- 11} m$

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