The Z-configuration in the following is

The order of priority(based on atomic no.) of groups attached to double bonded carbon is

In Options(1) & (2) ,  -H < -CH₃ (in case of C₁)

                                  -C₂H₅ < -C₃H₇ (in case of C₂)

In Option(3) ,  -H <  F (in case of C₁)

                       -Br < -Cl (in case of C₂)

If two high priority groups are of the same side to the double bond, then it is  Z-isomer.

If two high priority groups are of the opposite side to the double bond, then it is E-isomer.

$\therefore$ Option(2) represents Z-isomer.