The zener diode has a $V z = 30 V$ The current passing through the diode for the following circuit is ......... mA.

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answer is 9.

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Detailed Solution

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$\begin{array}{l} i = \frac{60}{4000} A \\ i_{1} = \frac{30}{5000} A \\ i - i_{1} = \frac{60}{4000} - \frac{30}{5000} = \frac{9}{1000} A \end{array}$
Current from zener diode
$i 2 = i − i 1 = 9 mA$

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