The zeroes of the polynomial: $x^{2} + 2 x + 1$ are

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0, 0

-1, 0

0, 1

-1, -1

answer is D.

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Detailed Solution

The polynomial equation is

x^{2} + 2 x + 1

.
Firstly we will split the middle term into two parts such that its multiplication will be equal to the product of the first term and the third term of the equation. Therefore, we get
⇒

x^{2} + x + x + 1

Now we will be taking x common from the first two terms and taking 1 common from the last two terms. Therefore the equation becomes
⇒x(x+1)+1(x+1)
Now we will take (x+1) common from the equation we get
⇒(x+1)(x+1)
Therefore, these are the factors of the equation. Now we will equate these factors to zero to get the value of x.
Therefore, we get
⇒x + 1 = 0
⇒x = −1
As both the factors are the same therefore the value of x is −1,−1
Hence, −1,−1 are the zeroes of the given polynomial.

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