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Q.

The zeroes of the polynomial $p (x) = 4 x^{2} - 12 x + 9$ are

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a

$- 3, - 4$

b

$\frac{3}{2}, \frac{3}{2}$

c

$3, 4$

d

$- \frac{3}{2}, - \frac{3}{2}$

answer is A.

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Detailed Solution

$(2 x)^{2} - 2 (3) (2 x) + 3^{2} = (2 x - 3)^{2}$

$x =$ $\frac{3}{2}, \frac{3}{2}$

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