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The zeroes of the quadratic polynomial $3 x 2 − x − 4$ are:

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− 4 3, − 1

43, − 1

43, 1

− 4 3, 1

answer is B.

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Detailed Solution

Given a polynomial

3 x 2 − x − 4

.
Using the middle term splitting method,

3 x 2 − x − 4

3 x 2 − (4 x − 3 x) − 4 = 0 3 x 2 − 4 x + 3 x − 4 = 0 x (3 x − 4) + 1 (3 x − 4) = 0 (3 x − 4) (x + 1) = 0

x = 43, − 1

are two zeros of the given polynomial.
Hence, option 2 is correct.

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