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The zeroes of the quadratic polynomial $4 u 2 + 8 u$ are:

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0, -3

0, -4

0, -2

0, -1

answer is C.

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Detailed Solution

Given a polynomial

4 u 2 + 8 u

.
Simply taking 4u common,

4 u 2 + 8 u

4 u (u + 2) = 0

(u + 2) (4 u + 0) = 0

u = 0, − 2

are 2 zeros of the given polynomial.
Hence, option 3 is correct.

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