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The zeroes of the quadratic polynomial $6 x 2 − 3 − 7 x$ are:

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32, − 1 3

− 3 2, − 1 3

32, 13

− 3 2, 13

answer is A.

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Detailed Solution

Given a polynomial

6 x 2 − 3 − 7 x

.
Using the middle term splitting method,

6 x 2 − 3 − 7 x

6 x 2 − 9 x + 2 x − 3 = 0

3 x (2 x − 3) + 1 (2 x − 3) = 0

(2 x − 3) (3 x + 1) = 0

x = 32, − 1 3

are 2 zeros of given polynomial.
Hence, option 1 is correct.

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