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Q.

The zeros of the equation x2+8x+9=0, can be


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a

x=-1±7

b

x=-2±7

c

x=4±7

d

x=-4±7  

answer is D.

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Detailed Solution

It is given that the equation is x2+8x+9=0.
Here we use the quadratic formula to solve the question i.e., -b±b2-4ac2a.
Comparing the values of the given equation with standard quadratic equation, ax2+bx+ c we get the values of a, b, c as a=1,b=8,c=9.
Substituting the given values in the quadratic formula,
x=-b±b2-4ac2a  x=-8±64-4(1)(9)2×1  x=-8±282  x=-8±272  x=-4±7
Zeros of the given equation are -4±7.
Hence, option 4.
 
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