The ${15}^{th}$ term of the AP: $6, 11, 16..........$ is ____________.

Steps to the derived $n^{th}$ term are given below

Here, $a$ (first value) = $6$, $d$ (difference between first and second value)= $11-6=5$, $n=15$

As we know,

 $$\begin{gathered} a_n = a + (n – 1) d \\ {a}_{15} = 6+ (15-1)\times 5 \\ = 6+14\times 5 \\ = 6+70 \\ {a}_{15 }= 76 \end{gathered}$$