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The $A (2, 3), B (- 2, 3)$ are two points. The locus of p which moves such that $|P A - P B| = 4$ is

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$y^{2} - 3 = 0$

$y + 3 = 0$

$y - 3 = 0$

$y^{2} + 3 = 0$

answer is B.

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Detailed Solution

$|P A - P B| = 4, A B = 4$ $\Rightarrow |P A - P B| = A B \Rightarrow L o c u s o f P i s u n i o n o f t w o r a y s w i t h v e r t i c e s A, B$

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