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Q.

The $(C - H)$ bond length order in hydrocarbons in which the hybridisation of carbon is ${sp}^{3}$ or ${sp}^{2}$ or $sp$

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a

$s p^{3} - s > s p^{2} - s > s p - s$

b

$sp - s = {sp}^{2} - s = {sp}^{3} - s$

c

$sp - s > {sp}^{2} - s > {sp}^{3} - s$

d

$s p^{3} - s > s p - s > s p^{2} - s$

answer is C.

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Detailed Solution

The bond length in hydrocarbon when the adjacent carbon has different hybridisation is in order.

Hydrocarbon: Ethane Ethene Ethyne
Bond length $1.09 A ° > 1.076 A ° > 1.06 A °$

$s p^{3} - s > s p^{2} - s > s p^{} - s$

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The (C-H) bond length order in hydrocarbons in which the hybridisation of carbon is sp3 or sp2 or sp