The $Cl - C - Cl$ angle in 1, 1, 2, 2, tetrachloroethene and tetrachloromethane respectively will be about

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$120^{0} - {109.5}^{0}$

${109.5}^{0} - 90^{0}$

$90^{0} - {109.5}^{0}$

${109.5}^{0} - 120^{0}$

answer is A.

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Detailed Solution

In 1, 1, 2, 2 tetrachloroethene, each carbon is ${sp}^{2} - hybridized$ thus having bond angle $120^{0}$ and in tetrachloromethane carbon is ${sp}^{3} - hybridized,$ hence bond angle is ${109.5}^{0}$

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