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$The Δ_{f} H^{\circ} for {CO}_{2} (g), CO (g) and H_{2} O (g) are - 393 .5, - 110 .5$ and -241.8 kJ/mol respectively, the standard enthalpy change
(in kJ) for the reaction ${CO}_{2} (g) + H_{2} (g) \to CO (g) + H_{2} O (g) is :$

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524.1

41.2

-262.5

-41.2

answer is B.

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Detailed Solution

$Δ H = Σ [Δ H_{f}^{\circ} products] - Σ [Δ H_{f}^{\circ} reactants]$

${ΔH}^{\circ} = [{ΔH}_{f}^{\circ} (CO) (g) + {ΔH}_{f}^{\circ} (H_{2} O) (g)] - [{ΔH}_{f}^{\circ} ({CO}_{2}) (g) + {ΔH}_{f}^{\circ} (H_{2}) (g)]$

$= [- 110 .5 + (- 241 .8)] - [- 393 .5 + 0] = 41 .2$

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