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Q.

The H.C.F of the polynomials p(x)=(x3)(x2+x2)  and q(x)=x25x+6 is (x3), then there L.C.M is 

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a

(x+3)(x1)(x24)

b

(x3)(x1)(x24)

c

(x+1)(x1)(x24)

d

(x+1)2(x1)(x24)

answer is C.

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Detailed Solution

L.C.M=productofthepolynomialsH.C.F

L.C.M=(x3)(x2+x2)(x25x+6)(x3)

=(x2+x2)(x25x+6)

=(x2+2xx2)(x22x3x+6)

=[x(x+2)1(x+2)][x(x2)3(x2)]

=(x+2)(x1)(x2)(x3)

=(x24)(x1)(x3)

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The H.C.F of the polynomials p(x)=(x−3)(x2+x−2)  and q(x)=x2−5x+6 is (x−3), then there L.C.M is