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Q.

The $K_{a}$ value for the acid HA is $1.0 \times 10^{- 6} .$ What is the value of K for the reaction ? $A^{-} + H_{3} O^{+} ⇌ HA + H_{2} O$

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a

$1.0 \times 10^{6}$

b

$1.0 \times 10^{- 3}$

c

$1.0 \times 10^{- 8}$

d

$1.0 \times 10^{8}$

answer is D.

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Detailed Solution

$HA (aq) ⇌ H^{+} + A^{-}$

$H_{3} O^{+} + A^{-} ⇌ HA + H_{2} O$

$Ka = \frac{[H_{3} O^{+}] [A^{-}]}{[HA] [H_{2} O]} = 1 \times 10^{- 6}$

${Ka}_{1} = \frac{[HA] [H_{2} O]}{[H_{3} O^{+}] [A^{-}]} = 1 \times 10^{6}$

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