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$T h e p a r a m e t r i c e q u a t i o n s o f t h e c i r c l e (x - 3)^{2} + (y - 2)^{2} = 100 a r e$

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$x = 3 + 10 \cos θ, y = 2 + 10 \sin θ$

$x = 1 + 5 \cos θ, y = 5 \sin θ$

$x = - 3 - 10 \cos θ, y = 2 - 10 \sin θ$

$x = - 1 + 10 \cos θ, y = - 6 + 10 \sin θ$

answer is A.

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Detailed Solution

$x = x_{1} + r \cos θ = 3 + 10 c o s θ y = y_{1} + r s i n θ = 2 + 10 s i n θ$

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