The $p_{ka}$ of a weak acid is 4.8. What is the ratio of [Salt]/ [Acid]; if a buffer of pH = 5.8 is to be prepared?

Given data: It is given to find out the ratio of [Salt]/ [Acid].

Concept used: pH = $p{K}_a+log\frac{\left[salt\right]}{\left[acid\right]}$

Explanation: pH = $p{K}_a+log\frac{\left[salt\right]}{\left[acid\right]}$

5.8 = 4.8 + $log\frac{\left[salt\right]}{\left[acid\right]}$

$log\frac{\left[salt\right]}{\left[acid\right]}$ = 5.8 – 4.8 = 1

$\frac{\left[salt\right]}{\left[acid\right]}$ = ${10}^1$ = 10

Hence, the answer is 10:1.