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The $p K_{a}$ of iodic acid $H I O_{3}$ is $\log 9$ . Calculate the $p H$ of a 1 $M$ $H I O_{3}$ solution.

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$\log 5$

$\log 6$

$\log 4$

$\log 3$

answer is D.

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Detailed Solution

${HIO}_{3} + Weak acid.$

$p H = \frac{1}{2} [p k_{a} - \log c]$

$= \frac{1}{2} [\log 9 - \log (1)]^{= 0}$

$p H = \frac{1}{2} \log 9$

$= \log (9)^{1 / 2}$

$= \log \sqrt{9}$

$p H$ $=$ $\log 3$

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