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Q.

There are 10 bags B1,B2,B3,……B10 which contain 21 22, ....30 different articles respectively. The total number of ways to bring out 10 articles from a bag is 

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a

 31C21

b

 31C20

c

 32C20

d

 31C20−21C10

answer is A.

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Detailed Solution

The required ways =

 21C10+22C10+23C10+……+30C10= 21C10+21C11+22C12+23C13+…+30C20−21C10=22C11+22C12+…+30C20−21C10=31C20−21C10

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