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There are 125 cells with an internal resistance $2 Ω$ and an external resistance $10 Ω$ . How cells should be arranged so that current in external resistance is maximum?
$m :$ number of rows, $n :$ number of cells in a row.

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$m = 5, n = 25$

$m = 25, n = 5$

$m = 4, n = 40$

$m = 40, n = 4$

answer is A.

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Detailed Solution

$m n = 125$

Current is maximum when

$R = \frac{n r}{m} ...... (i)$

$10 = \frac{n}{m} \times 2$

$n = 5 m$

$5 m^{2} = 125 \Rightarrow m = 5, n = 25... (i i)$

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