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There are 15 cards. Of these 10 have the letter 'I' printed on them and the other 5 have the letter 'T' printed on them. If three cards are picked up at random one after the other and kept in the same order, the probability of making the word IIT is

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$\frac{90}{15 \times 14 \times 13}$

$\frac{15}{182}$

$\frac{15}{32}$

$\frac{15}{91}$

answer is B.

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Detailed Solution

out 15 cards 10 are letter I, 5 letter T Printed.

E=Probability of making the word IIT is

$P (E) = \frac{10}{15} \times \frac{9}{14} \times \frac{5}{13} = \frac{15}{91}$

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