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Q.

There are 27 drops of a conducting fluid. Each has a radius r and they are charged to a potential V₀. These are combined to form a bigger drop. Its potential will be:

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a

V₀

b

29V₀

c

3V₀

d

9 V₀

answer is C.

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Detailed Solution

If q be the charge on each drop, charge on big drop is Q=27q.
If R be the radius of bigger drop, ⇒R=3r

$\begin{aligned} V_{1} = k \frac{q}{r} \\ V_{2} = k \frac{Q}{R} = k \frac{27 q}{3 r} = 9 k \frac{q}{r} = 9 V_{1} \end{aligned}$

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