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Q.

There are 3 different pairs of shoes in a basket. Now 3 persons come and pick the shoes randomly so that each gets 2. Let p be the probability that no one is able to wear shoes. Then value of  13p4−p is 

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answer is 2.

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Detailed Solution

 

 Total ways =n(S)= 6C2⋅4C2⋅2C23!×3!=6!2!2!2!3!×3!=90,  Favourable cases =n(E)=90-3!+C1   3×C1   3×2×2=48 ⇒  p=4890=815

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